Right i'm completely stuck on this question ...

Calculate the point between the charges Q1 and Q2 where the electric field strength 'E' is zero. Q1 is 0.35C and Q2 is 0.7C. They're 250m apart.

I might be being stupid but i'm very confused anyway!!

**0**

# Help Please!

Started by Cooldude, Oct 26 2007 07:53 PM

3 replies to this topic

### #1

Posted 26 October 2007 - 07:53 PM

### #2

Posted 28 October 2007 - 04:13 PM

anyone? i'm still stumped...

### #3

Posted 28 October 2007 - 06:37 PM

The first step is to write the distance at which the electric field strength is zero from to be , then the distance from is . And we're trying to find the point at which the resultant electric field strengths is zero, so this is going to be the point at which the magnitude of the electric field strength due to is the same as the magnitude of the electric field strength due to . So, mathematically,

.

.

Then solve this for r. You should get two solutions, one of which satisfies , and the other one should be ignored (I think this solution for will be negative, because since , there will be a point on the opposite side of from at which the magnitude of the electric field strengths are equal. Not that the resultant electric field strength is

Hope that helps.

.

.

Then solve this for r. You should get two solutions, one of which satisfies , and the other one should be ignored (I think this solution for will be negative, because since , there will be a point on the opposite side of from at which the magnitude of the electric field strengths are equal. Not that the resultant electric field strength is

*not*zero here, as both the electric fields are acting in the same direction.)Hope that helps.

HMFC - Founded 1874, beefing the Cabbage since 1875

### #4

Posted 29 October 2007 - 08:25 PM

ohhh ok.... already handed my homework in but i shall remember that.... thanks

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